Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 710: 7

Answer

$V_B-V_A = -32.0~V$

Work Step by Step

We can use Equation (24-18) to find the potential difference: $V_B-V_A = -\int_{A}^{B}~E~dx$ $V_B-V_A = -\int_{0}^{4.00}~(4.00~N/C)~x~dx$ $V_B-V_A = -\frac{(4.00~N/C)~x^2}{2}~\Big\vert_{0}^{4.00}$ $V_B-V_A = -[\frac{(4.00~N/C)~(4.00)^2}{2} - \frac{(4.00~N/C)~(0)^2}{2}]$ $V_B-V_A = -32.0~V$
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