Chapter 24 - Electric Potential - Problems - Page 710: 6a

$V_B-V_A=2.46V$

Work Step by Step

We can find $V_B-V_A$ as: $V_B-V_A=\frac{W}{e}$ We plug in the known values of $W$ and $e$ in the formula above to obtain: $V_B-V_A=\frac{3.94\times 10^{-19}}{1.6\times 10^{-19}}$ $V_B-V_A=2.46V$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.