Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 710: 3b

Answer

$ V = 7.7\times 10^3 m/s $

Work Step by Step

If all this energy is used to accelerate a 1000-kg car from rest, then: $$\Delta U = 0.5 m V^2 $$ $$ V = \sqrt \frac{2\Delta U}{m} $$ We plug in the known values to obtain: $ V = 7.7\times 10^3 m/s $
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