Answer
$q=3.3nC$
Work Step by Step
We know that
$V=K\frac{q}{r}$
This can be written as:
$q=\frac{V r}{K}$
We plug in the known values to obtain:
$q=\frac{200\times 0.15}{9\times 10^9}$
$q=3.3\times 10^{-9}$
$q=3.3nC$
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