## Fundamentals of Physics Extended (10th Edition)

$q=3.3nC$
We know that $V=K\frac{q}{r}$ This can be written as: $q=\frac{V r}{K}$ We plug in the known values to obtain: $q=\frac{200\times 0.15}{9\times 10^9}$ $q=3.3\times 10^{-9}$ $q=3.3nC$