Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems - Page 710: 8a

Answer

The electric potential at $x = 2.0~m$ is $~~30.0~V$

Work Step by Step

We can use Equation (24-21) to find the potential difference between two points: $\Delta V = -E~\Delta x$ The area under the $E$ versus $x$ graph is the negative of the potential difference. We can find the area under the graph between $x=0$ and $x = 2.0~m$: $Area = \frac{1}{2}(-20.0~N/C)(2.0~m)$ $Area = -20.0~V$ The potential difference between $x=0$ and $x = 2.0~m$ is $\Delta V = 20.0~V$ Since the electric potential at the origin is $10~V$, the electric potential at $x = 2.0~m$ is $30.0~V$
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