## Fundamentals of Physics Extended (10th Edition)

$V_C-V_A=2.46V$
It is clear from the figure that $B$ and $C$ are the same potential. Therefore, $V_B=V_C$ Hence, it an be concluded that: $V_C-V_A=V_B-V_A$ Also, from part (a), we know that: $V_B-V_A=2.46V$ Thus, it is clear that: $V_C-V_A=2.46V$