## Fundamentals of Physics Extended (10th Edition)

$\Delta S=8.8mm$
We know that: $E=\frac{\sigma}{2\epsilon_{\circ}}$ We plug in the known values to obtain: $E=\frac{0.10\times 10^{-6}}{2(8.85\times 10^{-12})}=5649.71\frac{N}{C}$ We also know that $\Delta S=\frac{V}{E}$ We plug in the known values to obtain: $\Delta S=\frac{50}{5649.71}=8.8\times 10^{-3}=8.8mm$