Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 24 - Electric Potential - Problems: 5

Answer

$\Delta S=8.8mm$

Work Step by Step

We know that: $E=\frac{\sigma}{2\epsilon_{\circ}}$ We plug in the known values to obtain: $E=\frac{0.10\times 10^{-6}}{2(8.85\times 10^{-12})}=5649.71\frac{N}{C}$ We also know that $\Delta S=\frac{V}{E}$ We plug in the known values to obtain: $\Delta S=\frac{50}{5649.71}=8.8\times 10^{-3}=8.8mm$
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