Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 39: 119d

Answer

When $t = 0$: $a = 0$ When $t = 1.0~s$: $a = -0.872~cm/s^2$ When $t = 2.0~s$: $a = -1.23~cm/s^2$

Work Step by Step

$y = (2.0~cm)~sin~(\frac{\pi t}{4})$ $v = (2.0~cm)(\frac{\pi}{4})~cos~(\frac{\pi t}{4})$ $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~(\frac{\pi t}{4})$ When $t = 0$: $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~(\frac{\pi t}{4})$ $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~[\frac{(\pi)(0)}{4}]$ $a = -(2.0~cm)(\frac{\pi}{4})^2~(0)$ $a = 0$ When $t = 1.0~s$: $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~(\frac{\pi t}{4})$ $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~[\frac{(\pi)(1.0)}{4}]$ $a = -(2.0~cm)(\frac{\pi}{4})^2~(\frac{\sqrt{2}}{2})$ $a = -0.872~cm/s^2$ When $t = 2.0~s$: $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~(\frac{\pi t}{4})$ $a = -(2.0~cm)(\frac{\pi}{4})^2~sin~[\frac{(\pi)(2.0)}{4}]$ $a = -(2.0~cm)(\frac{\pi}{4})^2~(1)$ $a = -1.23~cm/s^2$
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