Answer
The car would travel an additional $~~5.56~m$
Work Step by Step
Note that $200~km/h \approx 55.6~m/s$
We can find the additional distance the car travels if the reaction time increases by $100~ms$:
$x = v~t$
$x = (55.6~m/s)(0.100~s)$
$x = 5.56~m$
The car would travel an additional $~~5.56~m$.
