Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 39: 114c

Answer

$\Delta t=6.1s$

Work Step by Step

To find the time required to stop, use the kinematics equation $$a=\frac{\Delta v}{\Delta t}$$ Solve for $\Delta t$ to get $$\Delta t=\frac{\Delta v}{a}$$ Substitute known values of $a=-9.1m/s^2$ and $\Delta v=-55.6m/s$ to get a time of $$\Delta t =\frac{-55.6m/s^2}{-9.1m/s^2}=6.1s$$
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