Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems: 114b

Answer

$a=0.93g$

Work Step by Step

To express an acceleration in terms of $g$, remember that $$a=ng$$ where $n$ is the number of gees, g is the acceleration due to gravity, $a=9.8m/s^2$, and a is acceleration. Solving for n, the number of gees, yields $$n=\frac{a}{g}$$ Substituting known values of $g=9.8m/s^2$ and $a=9.1m/s^2$ yields an n value of $$n=\frac{9.1m/s^2}{9.8m/s^2}=0.93$$ Therefore, the acceleration is equal to $0.93g$.
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