Answer
$T_b = 15.25~T_r$
Work Step by Step
As we calculated in part (c):
$T_b = 6.1~s$
We can find $T_b$ in terms of $T_r$:
$\frac{T_b}{T_r} = \frac{6100~ms}{400~ms}$
$\frac{T_b}{T_r} = 15.25$
$T_b = 15.25~T_r$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 2 - Motion Along a Straight Line - Problems - Page 39: 114d
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