Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 39: 111a

Answer

10.18 s

Work Step by Step

As the acceleration is constant, the time taken by the sprinter to reach his top speed is obtained using the relation $x-x_{0}=\frac{1}{2}(v_{0}+v)t$ where $x-x_{0}=12.0\,m$ and $v_{0}+v=(0+11.0)m/s$ $\implies t=\frac{12.0\,m}{11.0\,m/s}\times2=2.18\,s$ As the speed is constant, the remaining time to complete the 100 m race is obtained using the relation: $Time\,interval=\frac{distance}{speed}=\frac{(100-12)m}{11.0\,m/s}=8.00\,s$ Total time for the 100 m race= $2.18\,s+8.00\,s=10.18\,s$.
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