Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 2 - Motion Along a Straight Line - Problems - Page 39: 102


$\Delta x=8.42m$

Work Step by Step

First, the speed 303km/h must be converted to meters per second using dimensional analysis. $$\frac{303km}{1hr}\times \frac{1hr}{60min}\times \frac{1min}{60s}\times \frac{1.0km}{1.0\times 10^3m}$$ $$=84.2m/s$$ Use the formula for velocity $$v=\frac{\Delta x}{\Delta t}$$ Solve for $\Delta x$. $$\Delta x =v\Delta t$$ Substitute known values of $t=0.1s$ and $v=84.2m/s$ to get $$\Delta x=(84.2m/s)(0.1s)=8.42m$$
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