Answer
$3.33$ cm
Work Step by Step
$$v_{max}=A\omega$$ $$A=\frac{v_{max}}{\omega}=v_{max}\sqrt\frac{m}{k}$$ $$=(1.11m/s)\sqrt{\frac{5.4095kg}{6000N/m}}$$ $$=0.0333m=3.33 cm$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 437: 33b
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