Answer
$K=200\frac{N}{m}$
Work Step by Step
We know that
$E_{mec}=\frac{1}{2}KA^2$
$K=\frac{2E_{mec}}{A^2}$
putting the values
$K=\frac{2\times1J}{(0.1m)^2}$
$K=200\frac{N}{m}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 15 - Oscillations - Problems - Page 437: 30a
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