Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 437: 30c

Answer

$f=1.91Hz$

Work Step by Step

We know that $f=\frac{\omega}{2\pi}$ but $v_{max}=A\omega$ where $A$ represents amplitude and $\omega$ is the angular velocity now $\omega=\frac{v_{max}}{A}=\frac{1.20}{0.1}=12\frac{rad}{s}$ Put the value of $\omega$ and $\pi$ in the very first equation, we get $f=\frac{12}{6.28}$ $f=1.91Hz$
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