Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 437: 31d

Answer

$X_m=86.6cm$

Work Step by Step

From law of conservation of energy total energy is conserved. That is $E=P.E+K.E=200+125=375J$ Then at turning point $E=\frac{1}{2}KX_m^2$ where $'X_m'$ is the amplitude $X_m^2=\frac{2E}{K}$ Take square root on both sides $X_m=\sqrt\frac{2E}{K}$ put the values $X_m=\sqrt\frac{2(375)}{1000}$ $X_m=0.866m$ or $X_m=86.6cm$
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