Answer
$1.11$ $m/s$
Work Step by Step
Using conservation of momentum, we get; $$p_o=p_f$$ $$mv_{o,m}+Mv_{o,M}=(M+m)v_{f,m+M}$$ $$v_{f,m+M}=\frac{mv_{o,m}+Mv_{o,M}}{M+m}$$ $$=\frac{(.0095)(630m/s)+(5.4kg)(0m/s)}{5.4kg+.0095kg}$$ $$=1.11m/s$$
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