Answer
$$
245 \mathrm{\ Pa}
$$
Work Step by Step
Since $p+\frac{1}{2} \rho v^{2}=$ const., the pressure difference is
$$
\Delta p=\frac{1}{2} \rho \Delta v^{2}=\frac{1}{2}\left(1000 \mathrm{kg} / \mathrm{m}^{3}\right)\left[(2.50 \mathrm{m} / \mathrm{s})^{2}-(2.40 \mathrm{m} / \mathrm{s})^{2}\right]=245 \mathrm{Pa}
$$
