Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 410: 58

Answer

$\Delta$p=1809045 (N/$m^{2}$)

Work Step by Step

According to bernoulli's eqt: p1 + $\frac{v1^{2}}{2}$ + $\theta$gh1 = p2 + $\frac{v2^{2}}{2}$ + $\theta$gh2 p1-p2= $\frac{9.5^{2}}{2}$ + 1000$\times$9.8$\times$180-$(\frac{0.4^{2}}{2}$ + 1000 $\times$9.8$\times$0) p1-p2= 1809045 (N/$m^{2}$)
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