Answer
$1$
Work Step by Step
The volume flow rate in the 1.9 cm diameter pipe is: $A_1v_1=56\;L/min$
The volume flow rate in the 1.3 cm diameter pipe is: $A_2v_2=26\;L/min$
Now,
$\frac{A_1v_1}{A_2v_2}=\frac{56}{26}$
or, $\frac{v_1}{v_2}=\frac{56}{26}\times\frac{A_2}{A_1}$
or, $\frac{v_1}{v_2}=\frac{56}{26}\times\frac{d_2^2}{d_1^2}$
or, $\frac{v_1}{v_2}=\frac{56}{26}\times\frac{1.3^2}{1.9^2}$
or, $\frac{v_1}{v_2}\approx1$
Therefore, the ratio of the speed is $1$
