Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 410: 56b

Answer

$\frac{R_{v_1}}{R_{v_2}}=\frac{1}{2}$

Work Step by Step

The mass flow rate is the same for the two holes $\rho_1A_1v_1=\rho_2A_2v_2$ or, $\rho_1R_{v_1}=\rho_2R_{v_2}$ where, $R_{v_1}$ and $R_{v_2}$ are the volume flow rates for the two tanks Therefore, $\frac{R_{v_1}}{R_{v_2}}=\frac{\rho_2}{\rho_1}$ or, $\boxed{\frac{R_{v_1}}{R_{v_2}}=\frac{1}{2}}\;\;\;\;[\because\;\frac{\rho_1}{\rho_2}=2]$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.