Answer
$\frac{\rho_1}{\rho_2}=2$
Work Step by Step
The mass flow rate is the same for the two holes
$\rho_1A_1v_1=\rho_2A_2v_2$
or, $\rho_1\frac{A_2}{2}v_1=\rho_2A_2v_2$
or, $\frac{\rho_1}{\rho_2}=\frac{2v_2}{v_1}$
Using the the Bernoulli’s equation, we obtain
$v_1=\sqrt {2gh}$
and $v_2=\sqrt {2gh}$
Therefore, $v_1=v_2$
Thus, the ratio becomes
$\boxed{\frac{\rho_1}{\rho_2}=2}$
