Answer
The water leaves the sprinkler holes at a speed of $~~8.1~m/s$
Work Step by Step
We can find the speed $v_2$ at which the water leaves the sprinkler holes:
$A_2~v_2 = A_1~v_1$
$24~\pi~r_2^2~v_2 = \pi~r_1^2~v_1$
$v_2 = \frac{r_1^2~v_1}{24~r_2^2}$
$v_2 = \frac{(0.95~cm)^2~(0.91~m/s)}{(24)~(0.065~cm)^2}$
$v_2 = 8.1~m/s$
The water leaves the sprinkler holes at a speed of $~~8.1~m/s$
