Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 14 - Fluids - Problems - Page 410: 53

Answer

$65.86\;W$

Work Step by Step

The power of the pump is equals to the total energy (kinetic energy+potential energy) of the water passing through the window per unit time. Therefore, the pump’s power is $P=\frac{1}{2}\rho_w(5\times\pi\times0.01^2)\times5^2+ \rho_w(5\times\pi\times0.01^2)\times9.81\times3$ or, $P=1000\times(5\times\pi\times0.01^2)\times(\frac{1}{2}\times25+9.81\times3)\;W$ or, $\boxed{P=65.86\;W}$
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