Answer
The horizontal component of the force on the bar from the hinge is $~~433~N$
Work Step by Step
To find the horizontal component of the force on the bar from the hinge $F_{hx}$, we can consider the net horizontal force on the bar:
$\sum F_x = 0$
$F_{hx} - (500~N)~cos~30.0^{\circ} = 0$
$F_{hx} = (500~N)~cos~30.0^{\circ}$
$F_{hx} = 433~N$
The horizontal component of the force on the bar from the hinge is $~~433~N$.
