Answer
The horizontal component of the force on the beam from the hinge is $~96~N$
Work Step by Step
To find $F_x$, the horizontal component of the force on the beam from the hinge, we can consider the horizontal forces exerted on the beam.
In part (a), we found that the tension $T$ in the wire is $~~T = 192~N$
We can find $F_x$:
$F_{net,x} = 0$
$T~sin~30.0^{\circ}-F_x = 0$
$F_x = T~sin~30.0^{\circ}$
$F_x = (192~N)~sin~30.0^{\circ}$
$F_x = 96~N$
The horizontal component of the force on the beam from the hinge is $~96~N$
