Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 323: 45a

Answer

The angular speed is $~~3.6~rev/s$

Work Step by Step

We can use conservation of angular momentum to find the new angular speed: $L_f = L_i$ $I_f~\omega_f = I_i~\omega_i$ $\omega_f = \frac{I_i~\omega_i}{I_f}$ $\omega_f = \frac{(6.0~kg~m^2)(1.2~rev/s)}{2.0~kg~m^2}$ $\omega_f = 3.6~rev/s$ The angular speed is $~~3.6~rev/s$.
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