Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 323: 38b

Answer

The angular velocity is $~~440~rad/s$

Work Step by Step

We can find the magnitude of the angular momentum: $L = \tau~t$ $L = (16~N\cdot m)(33\times 10^{-3}~s)$ $L = 0.528~kg~m^2/s$ We can find the angular velocity: $L = I\omega$ $\omega = \frac{L}{I}$ $\omega = \frac{0.528~kg~m^2/s}{1.2\times 10^{-3}~kg~m^2}$ $\omega = 440~rad/s$ The angular velocity is $~~440~rad/s$.
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