Answer
The magnitude of the angular momentum of the assembly is $~~3.9\times 10^{-3}~kg~m^2/s$
Work Step by Step
In part (a), we found that the rotational inertia of the assembly is $I = 4.6\times 10^{-3}~kg~m^2$
We can find the magnitude of the angular momentum of the assembly:
$L = I\omega$
$L = (4.6\times 10^{-3}~kg~m^2)(0.85~rad/s)$
$L = 3.9\times 10^{-3}~kg~m^2/s$
The magnitude of the angular momentum of the assembly is $~~3.9\times 10^{-3}~kg~m^2/s$
