Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 11 - Rolling, Torque, and Angular Momentum - Problems - Page 323: 41b

Answer

$L=I\omega$ $\omega=2\times3.1416\times(1\div T)$

Work Step by Step

First of all, we need to find out the magnitude of the constant constant angular velocity. for that, $\omega=2\times3.1416\times(1\div T)$ after that, we have to find out the magnitude of angular momentum through the formula $L=I\omega$ Then, I=1.8 kg.m^{2} and \omega=2.5 rad/s^{2}. so, L=4.5 kgm^{2}/s
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