Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 294: 108b

Answer

$0.5235\ m/s$

Work Step by Step

It is given that: angular speed $\omega = \frac{100}{3}\frac{rev}{min}$ We know that: 1 revolution = $2\pi$ radians 1 minute = 60 sec Now, we convert the given angular speed into radian per sec: $\omega = \frac{100\times 2\pi\ rad}{3\times 60\ s} = 3.49\ rad/s$ We know that the distance from the turnable axis i,e radius $r = 15\ cm= 0.15\ m$ This can be used to find the linear speed: linear speed $v=r\omega$ $v = (0.15\ m)(3.49\ rad/s) =0.5235\ m/s$
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