Answer
$I = 7.0~kg~m^2$
Work Step by Step
We can use the parallel axis theorem to find the rotational inertia:
$I = \frac{1}{12}ML^2+Md^2$
$I = \frac{1}{12}(3.0~kg)(4.0~m)^2+(3.0~kg)(1.0~m)^2$
$I = 7.0~kg~m^2$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 294: 103a
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