Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 294: 107b

Answer

$t = 14~s$

Work Step by Step

We can find the required angle: $\theta~r = x$ $\theta = \frac{x}{r}$ $\theta = \frac{5.6~m}{0.040~m}$ $\theta = 140~rad$ We can find the required time $t$: $\theta = \frac{1}{2}\alpha~t^2$ $t^2 = \frac{2\theta}{\alpha}$ $t = \sqrt{\frac{2\theta}{\alpha}}$ $t = \sqrt{\frac{(2)(140~rad)}{1.5~rad/s^2}}$ $t = 14~s$
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