Answer
The linear speed as seen by the pilot is $~~310~m/s$
Work Step by Step
We can express the angular speed in units of $rad/s$:
$\omega = (2000~rev/min)(\frac{2\pi~rad}{1~rev})(\frac{1~min}{60~s}) = 209.44~rad/s$
We can find the tangential speed:
$v_t = \omega~r$
$v_t = (209.44~rad/s)(1.5~m)$
$v_t = 310~m/s$
The linear speed as seen by the pilot is $~~310~m/s$
