Answer
$T_1 = 4.55~N$
Work Step by Step
In part (a), we found that $a = 1.57~m/s^2$
We can consider the forces on $m_1$ to find $T_1$:
$T_1 - m_1~g = m_1~a$
$T_1 = m_1~(g+a)$
$T_1 = (0.400~kg)~(9.8~m/s^2+1.57~m/s^2)$
$T_1 = 4.55~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 293: 83b
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
