Answer
$39.8\ rev$
Work Step by Step
We find the number of revolutions as:
$n=(250\ rad)\frac{1\ rev}{2\pi\ rad}$
$n=39.8\ rev$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 293: 90c
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