Answer
$154.8\ kg. m^2$
Work Step by Step
Given:
radius of spherical shell $r =1.90\ m$
applied torque $\tau =960\ N.m$
angular acceleration $\alpha = 6.20\ rad/s^2$
Formula for the torque is $\tau =I\alpha$
where $I$ is the moment of inertia
Therefore;
$I=\frac{\tau}{\alpha}$
$I=\frac{960\ N.m }{6.20\ rad/s^2}$
$I =154.8\ kg. m^2$
