Answer
$T_2 = 4.94~N$
Work Step by Step
In part (a), we found that $a = 1.57~m/s^2$
We can consider the forces on $m_2$ to find $T_2$:
$ m_2~g-T_2 = m_2~a$
$T_2 = m_2~(g-a)$
$T_2 = (0.600~kg)~(9.8~m/s^2-1.57~m/s^2)$
$T_2 = 4.94~N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 10 - Rotation - Problems - Page 293: 83c
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