Answer
$\alpha = 2.3~rad/s^2$
Work Step by Step
Without a pole, the only torque on the person is due to the gravitational force.
We can find the magnitude of the initial angular acceleration:
$\tau = I~\alpha$
$\alpha = \frac{\tau}{I}$
$\alpha = \frac{mg~d}{I}$
$\alpha = \frac{(70.0~kg)(9.8~m/s^2)(0.050~m)}{15.0~kg~m^2}$
$\alpha = 2.3~rad/s^2$
