Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 292: 71a

Answer

$\alpha = 31.4~rad/s^2$

Work Step by Step

We can find the angular acceleration: $\theta = \frac{1}{2}\alpha~t^2$ $\alpha = \frac{2~\theta}{t^2}$ $\alpha = \frac{(2)(0.130~rad)}{(0.0910~s)^2}$ $\alpha = 31.4~rad/s^2$
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