Answer
$a = 0.754~m/s^2$
Work Step by Step
We can find the angular acceleration:
$\theta = \frac{1}{2}\alpha~t^2$
$\alpha = \frac{2~\theta}{t^2}$
$\alpha = \frac{(2)(0.130~rad)}{(0.0910~s)^2}$
$\alpha = 31.4~rad/s^2$
We can find the magnitude of the acceleration of each block:
$a = \alpha~r$
$a = (31.4~rad/s^2)(0.0240~m)$
$a = 0.754~m/s^2$
