Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 292: 71c

Answer

$T_1 = 56.1~N$

Work Step by Step

In part (b), we found that $~~a = 0.754~m/s^2$ We can find $T_1$: $mg-T_1 = ma$ $T_1 = mg- ma$ $T_1 = m~(g- a)$ $T_1 = (6.20~kg)~(9.80~m/s^2- 0.754~m/s^2)$ $T_1 = 56.1~N$
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