Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems: 75

Answer

Please see the work below.

Work Step by Step

We know that the initial relative speed is $v_i=80-25=55\frac{Km}{h}=15.28\frac{m}{s}$ Now, we can find the final relative speed as follows $v_f^2=v_i^2-2ax$ We plug in the known values to obtain: $v_f^2=(15.28)^2+(2)(-2.1)(50)=23.41$ $v_f=4.8\frac{m}{s}$
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