Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems - Page 30: 54


Please see the work below.

Work Step by Step

We know that $\Delta d=\frac{v^2-v_{\circ}^2}{2a} $ We plug in the known values to obtain: $\Delta d=\frac{(3)^2}{2(9.8)}$ $\Delta d=0.46m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.