## Essential University Physics: Volume 1 (3rd Edition)

We know that (a) The average velocity is given as $v=\frac{v_1+v_2}{t}$ We plug in the known values to obtain: $v=\frac{32+18}{2}=25\frac{m}{s}$ and the time can be determined as $t=\frac{x}{v}$ $t=\frac{0.35}{25}=0.014s$ (b) We know that $a=\frac{\Delta v}{\Delta t}$ $a=\frac{18-32}{0.014}=-1000\frac{m}{s^2}$ Now we can find the thickness of snow as $d=\frac{v_f^2-v_i^2}{2a}$ We plug in the known values to obtain: $d=\frac{(0)^2-(32)^2}{(2)(-1000)}=.512 \ m$