Essential University Physics: Volume 1 (3rd Edition)

Published by Pearson
ISBN 10: 0321993721
ISBN 13: 978-0-32199-372-4

Chapter 2 - Exercises and Problems: 73

Answer

Please see the work below.

Work Step by Step

We know that $y=\frac{1}{2}g_{moon}t^2$ This simplifies to: $t=\sqrt{\frac{2y}{g_{moon}}}$ We plug in the known values to obtain: $t=\sqrt{\frac{2(12)}{1.62}}$ $t=3.8s$
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