Answer
Please see the work below.
Work Step by Step
We know that
$v^2=2gI_{\circ}d$
$v=\sqrt{2gI_{\circ}d}$
We plug in the known values to obtain:
$v=\sqrt{(2)(1.8)(100)}$
$v=19\frac{m}{s}$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 2 - Exercises and Problems - Page 30: 68
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
