## Essential University Physics: Volume 1 (3rd Edition)

We know that (a) $a=\frac{\Delta v}{\Delta t}$ We plug in the known values to obtain: $a=\frac{\frac{110}{3.6}}{(1.2)\times(60)}$ $a=0.42\frac{m}{s^2}$ (b) We know that the direction of acceleration is opposite to that of the speed. (c) As $x=\frac{v^2}{2a}$ We plug in the known values to obtain: $x=\frac{(\frac{110}{3.6})^2}{2(0.42)}$ $x=1100m$